Ответы к учебнику по математике за 2 класс 2 часть Рудницкая. Площадь фигуры. Единицы площади. Номер №11

Вычисли.
(3 * 4) : 6
(45 : 5) * 4
(28 : 4) * 6
(26 + 4) : 5
(51 − 50) * 12
(21 : 3) + 40
63 − (54 : 6)
28 + (28 : 4)
(90 − 50) : 5
36 : (46 − 40)
(66 − 59) * 0
(42 + 38) − 80

Ответ

(3 * 4) : 6 = 2
(45 : 5) * 4 = 36
(28 : 4) * 6 = 42
(26 + 4) : 5 = 6
(51 − 50) * 12 = 12
(21 : 3) + 40 = 47
63 − (54 : 6) = 54
28 + (28 : 4) = 35
(90 − 50) : 5 = 8
36 : (46 − 40) = 6
(66 − 59) * 0 = 0
(42 + 38) − 80 = 0
Вычисления:
(3 * 4) : 6 = 12 : 6 = 2
(45 : 5) * 4 = 9 * 4 = 36
(28 : 4) * 6 = 7 * 6 = 42
(26 + 4) : 5 = 30 : 5 = 6

$\begin{array}{r}\begin{array}{r}+\end{array}\underline{\begin{array}{r}26\\ 4\end{array}}\\ \begin{array}{r}30\end{array}\end{array}$
(51 − 50) * 12 = 1 * 12 = 12

$\begin{array}{r}\begin{array}{r}—\end{array}\underline{\begin{array}{r}51\\ 50\end{array}}\\ \begin{array}{r}1\end{array}\end{array}$
(21 : 3) + 40 = 7 + 40 = 47

$\begin{array}{r}\begin{array}{r}+\end{array}\underline{\begin{array}{r}7\\ 40\end{array}}\\ \begin{array}{r}47\end{array}\end{array}$
63 − (54 : 6) = 63 − 9 = 54

$\begin{array}{r}\begin{array}{r}—\end{array}\underline{\begin{array}{r}63\\ 9\end{array}}\\ \begin{array}{r}54\end{array}\end{array}$
28 + (28 : 4) = 28 + 7 = 35

$\begin{array}{r}\begin{array}{r}+\end{array}\underline{\begin{array}{r}28\\ 7\end{array}}\\ \begin{array}{r}35\end{array}\end{array}$
(90 − 50) : 5 = 40 : 5 = 8

$\begin{array}{r}\begin{array}{r}—\end{array}\underline{\begin{array}{r}90\\ 50\end{array}}\\ \begin{array}{r}40\end{array}\end{array}$
36 : (46 − 40) = 36 : 6 = 6

$\begin{array}{r}\begin{array}{r}—\end{array}\underline{\begin{array}{r}46\\ 40\end{array}}\\ \begin{array}{r}6\end{array}\end{array}$
(66 − 59) * 0 = 7 * 0 = 0

$\begin{array}{r}\begin{array}{r}—\end{array}\underline{\begin{array}{r}66\\ 59\end{array}}\\ \begin{array}{r}7\end{array}\end{array}$
(42 + 38) − 80 = 80 − 80 = 0

$\begin{array}{r}\begin{array}{r}+\end{array}\underline{\begin{array}{r}42\\ 38\end{array}}\\ \begin{array}{r}80\end{array}\end{array}$

$\begin{array}{r}\begin{array}{r}—\end{array}\underline{\begin{array}{r}80\\ 80\end{array}}\\ \begin{array}{r}0\end{array}\end{array}$